Departure: | Clayton, VIC |
Arrival: | Rosedale, VIC |
Fastest route: | 2h 3min |
Distance: | 170km |
Cheapest route: | $16.6 |
Transfers: | Between 0 and 1 |
Train companies: | V/Line |
One Passenger / One Trip
10:49
Clayton, VIC
Clayton Station
12:52
Rosedale, VIC
Rosedale Station
2h 3min
V/Line
$16.6
10:49
Clayton, VIC
Clayton Station
14:23
Rosedale, VIC
Rosedale Station
3h 34min
+
$25.8
10:49
Clayton, VIC
Clayton Station
13:13
Sale, VIC
Sale Station: Pettit Street
2h 24min
V/Line
$21.4
0h 52min layover
14:05
Sale, VIC
Sale Station: Pettit Street
14:23
Rosedale, VIC
Rosedale Station
0h 18min
V/Line
$4.4
The Clayton - Rosedale route has approximately 2 frequencies and its minimum duration is around 2h 3min. It is important you book your ticket in advance to avoid running out, since $16.6 tickets tend to run out quickly.
The distance between Clayton and Rosedale is around 170 kilometers and bus companies that can help you in your journey are: V/Line.
The train journey may vary depending on the stops. The minimum duration is usually around 2h 3min to cover 170 kilometers.
According to our data, the cheapest ticket costs $16.6 and leaves Clayton Station. You will not have to do any transfers, the trip will go direct to Rosedale Station.
The last train leaves at 10:49 from Clayton Station and arrives at 14:23 at Rosedale Station. It will take 3h 34min, its price is $25.8 and the number of changes will be 1.
Yes, there are direct train routes, their duration is usually around 2h 3min and the price is $16.6.