| Departure: | Alpine, TX | 
| Arrival: | Normal, IL | 
| Fastest route: | 37h 16min | 
| Distance: | 2001km | 
| Cheapest route: | $134 | 
| Transfers: | 0 | 
| Train companies: | Amtrak | 
One Passenger / One Trip
8:45pm
Alpine, TX
Alpine
11:01am
Normal, IL
Bloomington-Normal
37h 16min
Amtrak
Texas Eagle
$134
          The Alpine - Normal route has approximately 1 frequencies and its minimum duration is around 37h 16min. It is important you book your ticket in advance to avoid running out, since $134 tickets tend to run out quickly. 
 The distance between Alpine and Normal is around 2001 kilometers and bus companies that can help you in your journey are: Amtrak.
          
        
The train journey may vary depending on the stops. The minimum duration is usually around 37h 16min to cover 2001 kilometers.
According to our data, the cheapest ticket costs $134 and leaves Alpine. You will not have to do any transfers, the trip will go direct to Bloomington-Normal.
The last train leaves at 8:45pm from Alpine and arrives at 11:01am at Bloomington-Normal. It will take 37h 16min, its price is $134 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 37h 16min and the price is $134.