| Departure: | Jefferson City, MO | 
| Arrival: | Newton, KS | 
| Fastest route: | 6h 54min | 
| Distance: | 523km | 
| Cheapest route: | $64 | 
| Transfers: | Between 0 and 1 | 
| Train companies: | Amtrak | 
One Passenger / One Trip
6:22pm
Jefferson City, MO
Jefferson City
2:45am
Newton, KS
Newton
8h 23min
+
$70
6:22pm
Jefferson City, MO
Jefferson City
9:40pm
Kansas City, MO
Kansas City
3h 18min
Amtrak
Missouri River Runner
$34
1h 5min layover
10:45pm
Kansas City, MO
Kansas City
2:45am
Newton, KS
Newton
4h 0min
Amtrak
Southwest Chief
$36
7:51pm
Jefferson City, MO
Jefferson City
2:45am
Newton, KS
Newton
6h 54min
Amtrak
Southwest Chief
$64
          The Jefferson City - Newton route has approximately 2 frequencies and its minimum duration is around 6h 54min. It is important you book your ticket in advance to avoid running out, since $64 tickets tend to run out quickly. 
 The distance between Jefferson City and Newton is around 523 kilometers and bus companies that can help you in your journey are: Amtrak.
          
        
The train journey may vary depending on the stops. The minimum duration is usually around 6h 54min to cover 523 kilometers.
According to our data, the cheapest ticket costs $64 and leaves Jefferson City. You will not have to do any transfers, the trip will go direct to Newton.
The last train leaves at 7:51pm from Jefferson City and arrives at 2:45am at Newton. It will take 6h 54min, its price is $64 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 6h 54min and the price is $64.