| Departure: | Jefferson City, MO | 
| Arrival: | Warrensburg, MO | 
| Fastest route: | 1h 44min | 
| Distance: | 157km | 
| Cheapest route: | $19 | 
| Transfers: | 0 | 
| Train companies: | Amtrak | 
One Passenger / One Trip
11:36am
Jefferson City, MO
Jefferson City
1:20pm
Warrensburg, MO
Warrensburg
1h 44min
Amtrak
Missouri River Runner
$19
6:22pm
Jefferson City, MO
Jefferson City
8:09pm
Warrensburg, MO
Warrensburg
1h 47min
Amtrak
Missouri River Runner
$19
          The Jefferson City - Warrensburg route has approximately 2 frequencies and its minimum duration is around 1h 44min. It is important you book your ticket in advance to avoid running out, since $19 tickets tend to run out quickly. 
 The distance between Jefferson City and Warrensburg is around 157 kilometers and bus companies that can help you in your journey are: Amtrak.
          
        
The train journey may vary depending on the stops. The minimum duration is usually around 1h 44min to cover 157 kilometers.
According to our data, the cheapest ticket costs $19 and leaves Jefferson City. You will not have to do any transfers, the trip will go direct to Warrensburg.
The last train leaves at 6:22pm from Jefferson City and arrives at 8:09pm at Warrensburg. It will take 1h 47min, its price is $19 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 1h 44min and the price is $19.