| Departure: | Lakeland, FL | 
| Arrival: | Deerfield Beach, FL | 
| Fastest route: | 3h 40min | 
| Distance: | 304km | 
| Cheapest route: | $30 | 
| Transfers: | Between 0 and 1 | 
| Train companies: | Amtrak | 
One Passenger / One Trip
1:13pm
Lakeland, FL
Lakeland - Departure 91 North Arrival 92 South
4:53pm
Deerfield Beach, FL
Deerfield Beach
3h 40min
Amtrak
Silver Star
$30
1:13pm
Lakeland, FL
Lakeland - Departure 91 North Arrival 92 South
5:25pm
Deerfield Beach, FL
Deerfield Beach
4h 12min
+
$39
1:13pm
Lakeland, FL
Lakeland - Departure 91 North Arrival 92 South
2:16pm
Sebring, FL
Sebring
1h 3min
Amtrak
Silver Star
$15
0h 38min layover
2:54pm
Sebring, FL
Sebring
5:25pm
Deerfield Beach, FL
Deerfield Beach
2h 31min
Amtrak
Silver Meteor
$24
          The Lakeland - Deerfield Beach route has approximately 2 frequencies and its minimum duration is around 3h 40min. It is important you book your ticket in advance to avoid running out, since $30 tickets tend to run out quickly. 
 The distance between Lakeland and Deerfield Beach is around 304 kilometers and bus companies that can help you in your journey are: Amtrak.
          
        
The train journey may vary depending on the stops. The minimum duration is usually around 3h 40min to cover 304 kilometers.
According to our data, the cheapest ticket costs $30 and leaves Lakeland - Departure 91 North Arrival 92 South. You will not have to do any transfers, the trip will go direct to Deerfield Beach.
The last train leaves at 1:13pm from Lakeland - Departure 91 North Arrival 92 South and arrives at 5:25pm at Deerfield Beach. It will take 4h 12min, its price is $39 and the number of changes will be 1.
Yes, there are direct train routes, their duration is usually around 3h 40min and the price is $30.