| Departure: | Normal, IL | 
| Arrival: | McGregor, TX | 
| Fastest route: | 23h 56min | 
| Distance: | 1449km | 
| Cheapest route: | $106 | 
| Transfers: | 0 | 
| Train companies: | Amtrak | 
One Passenger / One Trip
4:04pm
Normal, IL
Bloomington-Normal
4:00pm
McGregor, TX
McGregor
23h 56min
Amtrak
Texas Eagle
$106
4:04pm
Normal, IL
Bloomington-Normal
4:00pm
McGregor, TX
McGregor
23h 56min
Amtrak
Texas Eagle
$133
          The Normal - McGregor route has approximately 2 frequencies and its minimum duration is around 23h 56min. It is important you book your ticket in advance to avoid running out, since $106 tickets tend to run out quickly. 
 The distance between Normal and McGregor is around 1449 kilometers and bus companies that can help you in your journey are: Amtrak.
          
        
The train journey may vary depending on the stops. The minimum duration is usually around 23h 56min to cover 1449 kilometers.
According to our data, the cheapest ticket costs $106 and leaves Bloomington-Normal. You will not have to do any transfers, the trip will go direct to McGregor.
The last train leaves at 4:04pm from Bloomington-Normal and arrives at 4:00pm at McGregor. It will take 23h 56min, its price is $133 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 23h 56min and the price is $106.