Departure: | Rhinecliff, NY |
Arrival: | Normal, IL |
Fastest route: | 25h 59min |
Distance: | 1456km |
Cheapest route: | $128 |
Transfers: | 2 |
Train companies: | Amtrak |
One Passenger / One Trip
3:00pm
Rhinecliff, NY
Rhinecliff
3:59pm
Normal, IL
Bloomington-Normal
25h 59min
++
$128
3:00pm
Rhinecliff, NY
Rhinecliff
5:40pm
Utica, NY
Utica
2h 40min
Amtrak
Empire Service
$40
3h 8min layover
8:48pm
Utica, NY
Utica
9:45am
Chicago, IL
Chicago - Union Station
13h 57min
Amtrak
Lake Shore Limited
$74
4h 0min layover
1:45pm
Chicago, IL
Chicago - Union Station
3:59pm
Normal, IL
Bloomington-Normal
2h 14min
Amtrak
Texas Eagle
$14
The Rhinecliff - Normal route has approximately 1 frequencies and its minimum duration is around 25h 59min. It is important you book your ticket in advance to avoid running out, since $128 tickets tend to run out quickly.
The distance between Rhinecliff and Normal is around 1456 kilometers and bus companies that can help you in your journey are: Amtrak.
Remember that the number of transfers to be made will be at least 2 so in some cases you should book the tickets separately.
The train journey may vary depending on the stops. The minimum duration is usually around 25h 59min to cover 1456 kilometers.
According to our data, the cheapest ticket costs $128 and leaves Rhinecliff. If you decide to make this journey you will have to do 2 stops before reaching Bloomington-Normal.
The last train leaves at 3:00pm from Rhinecliff and arrives at 3:59pm at Bloomington-Normal. It will take 25h 59min, its price is $128 and the number of changes will be 2.
We do not have direct routes in our database. The minimum number of transfers will be 2 transshipments and the total duration of the trip will be approximately 25h 59min