| Departure: | Waterbury, VT |
| Arrival: | Somerdale, NJ |
| Fastest route: | 12h 21min |
| Distance: | 613km |
| Cheapest route: | $149.25 |
| Transfers: | 2 |
| Train companies: | Amtrak |
One Passenger / One Trip
10:10am
Waterbury, VT
Waterbury-Stowe
10:31pm
Somerdale, NJ
Lindenwold - NJ Transit Station
12h 21min
++
$149.25
10:10am
Waterbury, VT
Waterbury-Stowe
8:30pm
Wilmington, DE
Wilmington
10h 20min
Amtrak
Vermonter
$121
0h 13min layover
8:43pm
Wilmington, DE
Wilmington
9:07pm
Philadelphia, PA
Philadelphia - 30th Street Station
0h 24min
Amtrak
Northeast Regional
$23
0h 45min layover
9:52pm
Philadelphia, PA
Philadelphia - 30th Street Station
10:31pm
Somerdale, NJ
Lindenwold - NJ Transit Station
0h 39min
Amtrak
NJ Transit Train
$5.25
The Waterbury - Somerdale route has approximately 1 frequencies and its minimum duration is around 12h 21min. It is important you book your ticket in advance to avoid running out, since $149.25 tickets tend to run out quickly.
The distance between Waterbury and Somerdale is around 613 kilometers and bus companies that can help you in your journey are: Amtrak.
Remember that the number of transfers to be made will be at least 2 so in some cases you should book the tickets separately.
The train journey may vary depending on the stops. The minimum duration is usually around 12h 21min to cover 613 kilometers.
According to our data, the cheapest ticket costs $149.25 and leaves Waterbury-Stowe. If you decide to make this journey you will have to do 2 stops before reaching Lindenwold - NJ Transit Station.
The last train leaves at 10:10am from Waterbury-Stowe and arrives at 10:31pm at Lindenwold - NJ Transit Station. It will take 12h 21min, its price is $149.25 and the number of changes will be 2.
We do not have direct routes in our database. The minimum number of transfers will be 2 transshipments and the total duration of the trip will be approximately 12h 21min