| Departure: | Waterloo, IN |
| Arrival: | Pennsauken Township, NJ |
| Fastest route: | 18h 45min |
| Distance: | 983km |
| Cheapest route: | $297.25 |
| Transfers: | 2 |
| Train companies: | Amtrak |
One Passenger / One Trip
10:23pm
Waterloo, IN
Waterloo
5:08pm
Pennsauken Township, NJ
Pennsauken - NJ Transit Service
18h 45min
++
$297.25
10:23pm
Waterloo, IN
Waterloo
1:05pm
Washington, DC
Washington - Union Station
14h 42min
Amtrak
Capitol Limited
$81
0h 55min layover
2:00pm
Washington, DC
Washington - Union Station
3:30pm
Philadelphia, PA
Philadelphia - 30th Street Station
1h 30min
Amtrak
Acela Express
$212
1h 17min layover
4:47pm
Philadelphia, PA
Philadelphia - 30th Street Station
5:08pm
Pennsauken Township, NJ
Pennsauken - NJ Transit Service
0h 21min
Amtrak
NJ Transit Train
$4.25
The Waterloo - Pennsauken Township route has approximately 1 frequencies and its minimum duration is around 18h 45min. It is important you book your ticket in advance to avoid running out, since $297.25 tickets tend to run out quickly.
The distance between Waterloo and Pennsauken Township is around 983 kilometers and bus companies that can help you in your journey are: Amtrak.
Remember that the number of transfers to be made will be at least 2 so in some cases you should book the tickets separately.
The train journey may vary depending on the stops. The minimum duration is usually around 18h 45min to cover 983 kilometers.
According to our data, the cheapest ticket costs $297.25 and leaves Waterloo. If you decide to make this journey you will have to do 2 stops before reaching Pennsauken - NJ Transit Service.
The last train leaves at 10:23pm from Waterloo and arrives at 5:08pm at Pennsauken - NJ Transit Service. It will take 18h 45min, its price is $297.25 and the number of changes will be 2.
We do not have direct routes in our database. The minimum number of transfers will be 2 transshipments and the total duration of the trip will be approximately 18h 45min